Andrey Rublev vs João Fonseca Prediction: bet on the experienced player to win

Prediction for the ATP Australian Open match which will take place on January 14. Who will turn out to be stronger? Check the team conditions! Several betting options are available.

Andrey Rublev

After a disappointing final in Turin, where Andrey suffered three defeats in three matches, the Russian played four exhibition matches in the UAE at the end of December and achieved 4 wins. In the UAE Rublyov was stronger than Thompson, Kyrios, Tsitsipas and Nagal. Rublev started the official season poorly, losing in Hong Kong to Hungarian Marozhan in his first match at the tournament. The match lasted two hours, the score of the meeting 7:5, 3:6, 6:3 in favor of Fabian.

João Fonseca

João was last season's opener, the 18-year-old became the Next Gen triumphant at the end of December 2024, outlasting Tien in the final. In early 2025, the Brazilian won the Challenger in Canberra, outplaying American Quinn in the final. And in Melbourne, Fonseca had already played three matches as part of the qualification process and had not lost a set, knocking out Gomes, Wong and Tiranete. The match against Tiranete lasted an hour and 16 minutes and Fonseca won it 6-4, 6-1. During the game, the young Brazilian made 5 aces with two double faults, won 83% of points on first serve and 69% on second serve.

Expert Betting Tips

Rublev was unlucky with the draw, having such a promising opponent as Fonseca as early as the first round. The Brazilian has a long winning streak, but it is worth noting that most of his opponents are not top-level tennis players, the strongest being Fils and Menshik, ranked 21st and 48th in the ATP, respectively, so the Brazilian has not competed with players of Rublev's level. Rublev himself is probably aware of the prodigy's recent successes and will take the upcoming game seriously, without any underestimation. We doubt that the Russian is in for an easy ride, but we'll give the advantage to the more status and experience of Andrey.